I have a question that could be appropriate only for Physics Stack Exchange (and not for EESE), so I thought it would be a good idea to post it here on meta, so I could get a confirmation. Here goes the body of said question:
A bit of context
I came up with this question after someone suggested that two fuses are better than a main one in the below configuration. The converters are SMPSs which regulate output voltage.
Now someone justified that F1 and F2 are a better implementation through the following example: both converters are functioning within normal limits, each drawing 1A (and F1 and F2 are both designed to trip at 2A). If Converter 1 would fail open and Converter 2 would continue working normally, then during the finite instant when the aforementioned conditions start applying, as current cannot change instantly and has only one path to follow from supply to ground, the 2A will flow through Converter 2 and potentially damage it. Since F2 is there, it would protect against the over-current condition. If converters reverse roles in the same scenario, F1 will be there to open the circuit.
The justification basically says that the fuses are there to protect against an open-circuit event...instead of a short-circuit.
Main part
Now, remove the converters and the loads and place two real-world resistors between each fuse and ground, both (resistors) drawing 1A normally. Again, the total current drawn from the power supply would be 2 A.
The questions are:
1) If one removes a resistor (ceteris paribus), will the remaining other experience the 2A through for a very short, but finite amount of time? If it does, can it be due to something else, other than parasitic inductance?
2) Does 1) mean, if true, that ohm's law only applies if the time-step (or time scale) is large enough?
3) If 1) is true, is it worth taking into account this effect from an engineering perspective-i.e. during that short finite time, the 2A could damage the remaining resistor?
